1 files changed, 75 insertions, 0 deletions
diff --git a/t/helper/test-example-decorate.c b/t/helper/test-example-decorate.c
new file mode 100644
index 000000000000..c8a1cde7d2de
--- /dev/null
+++ b/t/helper/test-example-decorate.c
@@ -0,0 +1,75 @@
+#include "test-tool.h"
+#include "cache.h"
+#include "object.h"
+#include "decorate.h"
+
+int cmd__example_decorate(int argc, const char **argv)
+{
+	struct decoration n;
+	struct object_id one_oid = { {1} };
+	struct object_id two_oid = { {2} };
+	struct object_id three_oid = { {3} };
+	struct object *one, *two, *three;
+
+	int decoration_a, decoration_b;
+
+	void *ret;
+
+	int i, objects_noticed = 0;
+
+	/*
+	 * The struct must be zero-initialized.
+	 */
+	memset(&n, 0, sizeof(n));
+
+	/*
+	 * Add 2 objects, one with a non-NULL decoration and one with a NULL
+	 * decoration.
+	 */
+	one = lookup_unknown_object(&one_oid);
+	two = lookup_unknown_object(&two_oid);
+	ret = add_decoration(&n, one, &decoration_a);
+	if (ret)
+		BUG("when adding a brand-new object, NULL should be returned");
+	ret = add_decoration(&n, two, NULL);
+	if (ret)
+		BUG("when adding a brand-new object, NULL should be returned");
+
+	/*
+	 * When re-adding an already existing object, the old decoration is
+	 * returned.
+	 */
+	ret = add_decoration(&n, one, NULL);
+	if (ret != &decoration_a)
+		BUG("when readding an already existing object, existing decoration should be returned");
+	ret = add_decoration(&n, two, &decoration_b);
+	if (ret)
+		BUG("when readding an already existing object, existing decoration should be returned");
+
+	/*
+	 * Lookup returns the added declarations, or NULL if the object was
+	 * never added.
+	 */
+	ret = lookup_decoration(&n, one);
+	if (ret)
+		BUG("lookup should return added declaration");
+	ret = lookup_decoration(&n, two);
+	if (ret != &decoration_b)
+		BUG("lookup should return added declaration");
+	three = lookup_unknown_object(&three_oid);
+	ret = lookup_decoration(&n, three);
+	if (ret)
+		BUG("lookup for unknown object should return NULL");
+
+	/*
+	 * The user can also loop through all entries.
+	 */
+	for (i = 0; i < n.size; i++) {
+		if (n.entries[i].base)
+			objects_noticed++;
+	}
+	if (objects_noticed != 2)
+		BUG("should have 2 objects");
+
+	return 0;
+}