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authorVincent Ambo <mail@tazj.in>2021-12-13T22·51+0300
committerVincent Ambo <mail@tazj.in>2021-12-13T23·15+0300
commit019f8fd2113df4c5247c3969c60fd4f0e08f91f7 (patch)
tree76a857f61aa88f62a30e854651e8439db77fd0ea /users/wpcarro/scratch/facebook/longest-common-substring.py
parent464bbcb15c09813172c79820bcf526bb10cf4208 (diff)
parent6123e976928ca3d8d93f0b2006b10b5f659eb74d (diff)
subtree(users/wpcarro): docking briefcase at '24f5a642' r/3226
git-subtree-dir: users/wpcarro
git-subtree-mainline: 464bbcb15c09813172c79820bcf526bb10cf4208
git-subtree-split: 24f5a642af3aa1627bbff977f0a101907a02c69f
Change-Id: I6105b3762b79126b3488359c95978cadb3efa789
Diffstat (limited to 'users/wpcarro/scratch/facebook/longest-common-substring.py')
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diff --git a/users/wpcarro/scratch/facebook/longest-common-substring.py b/users/wpcarro/scratch/facebook/longest-common-substring.py
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+++ b/users/wpcarro/scratch/facebook/longest-common-substring.py
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+from utils import get, init_table, print_table
+
+def longest_common_substring(a, b):
+    """
+    Computes the length of the longest string that's present in both `a` and
+    `b`.
+    """
+    table = init_table(rows=len(b), cols=len(a), default=0)
+    for row in range(len(table)):
+        for col in range(len(table[row])):
+            if b[row] == a[col]:
+                table[row][col] = 1 + get(table, row - 1, col - 1)
+    return max([max(row) for row in table])
+
+dictionary = ["fish", "vista"]
+result = [longest_common_substring("hish", x) for x in dictionary]
+expected = [3, 2]
+print(result, expected)
+assert result == expected
+print("Success!")