diff options
author | Vincent Ambo <mail@tazj.in> | 2021-12-13T22·51+0300 |
---|---|---|
committer | Vincent Ambo <mail@tazj.in> | 2021-12-13T23·15+0300 |
commit | 019f8fd2113df4c5247c3969c60fd4f0e08f91f7 (patch) | |
tree | 76a857f61aa88f62a30e854651e8439db77fd0ea /users/wpcarro/scratch/facebook/interview-cake/linked-list-cycles.py | |
parent | 464bbcb15c09813172c79820bcf526bb10cf4208 (diff) | |
parent | 6123e976928ca3d8d93f0b2006b10b5f659eb74d (diff) |
subtree(users/wpcarro): docking briefcase at '24f5a642' r/3226
git-subtree-dir: users/wpcarro git-subtree-mainline: 464bbcb15c09813172c79820bcf526bb10cf4208 git-subtree-split: 24f5a642af3aa1627bbff977f0a101907a02c69f Change-Id: I6105b3762b79126b3488359c95978cadb3efa789
Diffstat (limited to 'users/wpcarro/scratch/facebook/interview-cake/linked-list-cycles.py')
-rw-r--r-- | users/wpcarro/scratch/facebook/interview-cake/linked-list-cycles.py | 70 |
1 files changed, 70 insertions, 0 deletions
diff --git a/users/wpcarro/scratch/facebook/interview-cake/linked-list-cycles.py b/users/wpcarro/scratch/facebook/interview-cake/linked-list-cycles.py new file mode 100644 index 000000000000..523ecd959daf --- /dev/null +++ b/users/wpcarro/scratch/facebook/interview-cake/linked-list-cycles.py @@ -0,0 +1,70 @@ +def contains_cycle(node): + """ + Return True if the linked-list, `node`, contains a cycle. + """ + if not node: + return False + a = node + b = node.next + while a != b: + a = a.next + if b and b.next and b.next.next: + b = b.next.next + else: + return False + return True + +################################################################################ +# Bonus +################################################################################ + +def first_node_in_cycle(node): + """ + Given that the linked-list, `node`, contains a cycle, return the first + element of that cycle. + """ + # enter the cycle + a = node + b = node.next + while a != b: + a = a.next + b = b.next.next + + # get the length of the cycle + beg = a + a = a.next + n = 1 + while a != beg: + a = a.next + n += 1 + + # run b n-steps ahead of a + a = node + b = node + for _ in range(n): + b = b.next + + # where they intersect is the answer + while a != b: + a = a.next + b = b.next + return a + +################################################################################ +# Tests +################################################################################ + +class Node(object): + def __init__(self, value, next=None): + self.value = value + self.next = next + def __repr__(self): + return "Node({}) -> ...".format(self.value) + +d = Node('d') +c = Node('c', d) +b = Node('b', c) +a = Node('a', b) +d.next = b + +print(first_node_in_cycle(a)) |