function-trace: always show the trace

If the user invokes nix with --trace-function-calls it means that they
want to see the trace.

(cherry picked from commit 619cc4af855fab7b0400586a4fd40745b23e72ad)

1 files changed, 2 insertions, 2 deletions

diff --git a/src/libexpr/function-trace.hh b/src/libexpr/function-trace.hh
index 8234b760312f..8b0ec848d5a8 100644
--- a/src/libexpr/function-trace.hh
+++ b/src/libexpr/function-trace.hh
@@ -12,13 +12,13 @@ struct FunctionCallTrace
     FunctionCallTrace(const Pos & pos) : pos(pos) {
         auto duration = std::chrono::high_resolution_clock::now().time_since_epoch();
         auto ns = std::chrono::duration_cast<std::chrono::nanoseconds>(duration);
-        vomit("function-trace entered %1% at %2%", pos, ns.count());
+        printMsg(lvlInfo, "function-trace entered %1% at %2%", pos, ns.count());
     }
 
     ~FunctionCallTrace() {
         auto duration = std::chrono::high_resolution_clock::now().time_since_epoch();
         auto ns = std::chrono::duration_cast<std::chrono::nanoseconds>(duration);
-        vomit("function-trace exited %1% at %2%", pos, ns.count());
+        printMsg(lvlInfo, "function-trace exited %1% at %2%", pos, ns.count());
     }
 };
 }