Add coding exercises for Facebook interviews

Add attempts at solving coding problems to Briefcase.

1 files changed, 42 insertions, 0 deletions

diff --git a/scratch/facebook/knapsack-faq.py b/scratch/facebook/knapsack-faq.py
new file mode 100644
index 000000000000..ae04f5eb96c0
--- /dev/null
+++ b/scratch/facebook/knapsack-faq.py
@@ -0,0 +1,42 @@
+from utils import get, init_table, print_table
+
+# This problem has a few variants:
+#   - limited supply of each item
+#   - unlimited supply of each item
+#   - fractional amounts of each item (e.g. rice)
+
+def max_haul(capacity, items):
+    min_kg = min([kg for _, kg in items])
+    max_kg = max([kg for _, kg in items])
+
+    cols = int(max_kg / min_kg)
+    fr_col_index = lambda index: min_kg * index + min_kg
+    to_col_index = lambda capacity: int((capacity - min_kg) * cols / max_kg)
+
+    table = init_table(rows=len(items), cols=cols, default=0)
+    for row in range(len(table)):
+        for col in range(len(table[row])):
+            curr_capacity = fr_col_index(col)
+            value, kg = items[row]
+
+            if kg > curr_capacity:
+                a = 0
+            else:
+                a = value + get(table, row - 1, to_col_index(curr_capacity - kg))
+
+            b = get(table, row - 1, col)
+            table[row][col] = max([a, b])
+        print_table(table)
+    return table[-1][-1]
+
+guitar = (1500, 1)
+stereo = (3000, 4)
+laptop = (2000, 3)
+necklace = (2000, 0.5)
+items = [necklace, guitar, stereo, laptop]
+capacity = 4
+result = max_haul(capacity, items)
+expected = 4000
+print(result, expected)
+assert result == expected
+print("Success!")